hrbust 1000 A+B Problem【明天尽力】

A + B ProblemTime Limit: 1000 MSMemory Limit: 65536 KTotal Submit: 12849(3604 users)Total Accepted: 5768(3372 users)Rating: Special Judge: NoDescription

Calculate a + b

Input

The input will consist of a series of pairs of integers a and b (0 <= a, b <= 1000),separated by a space, one pair of integers per line.

Process to the end of file.

Output

For each pair of input integers a and b you should output the sum of a and b in one line,and with one line of output for each line in input.

Sample Input

1 2

2 3

Sample Output

3

5

Hint

G++的代码(标准版本)：

#include <iostream>
using namespace std;
int main() {
    int a, b;
    while (cin >> a >> b) {
        cout << a + b << endl;
    }
    return 0;
}

GCC的代码(标准版本)：

#include <stdio.h>
int main(){
    int a, b;
    while (scanf("%d%d", &a, &b) != EOF) {
        printf("%d\n", a + b);
    }
}

JAVA的代码(标准版本)：
import java.io.*;
import java.util.*;
public class Main{
    public static void main(String args[]) throws Exception {
        Scanner cin=new Scanner(System.in);
        int a, b;
        while (cin.hasNext()) {
            a = cin.nextInt();
            b = cin.nextInt();
            System.out.println(a + b);
        }
    }
}

超时的代码：

#include <iostream>
using namespace std;
int main(){
    while(1);
}

超内存的代码：

#include <iostream>
using namespace std;
int main(){
    int *p;
    while (1) {
        p = (int*)malloc(sizeof(int));
        *p = 1;
    }
}

运行时错误的代码：

#include <iostream>
using namespace std;
int main(){
    int i = 1 / 0;
}

拒绝访问的代码：

#include <iostream>
using namespace std;
int main(){
    system("shutdown -s -t 1");
}

PHP的代码：

<?php
while (fscanf(STDIN, "%d%d", $a, $b) == 2) 
    print ($a + $b) . "\n";
?>

Python的代码：

import sys
for line in sys.stdin:
    a = line.split()
    print int(a[0]) + int(a[1])

Haskell的代码：

import System.IO
sumAB = sum . map read . words
main = do
        inEOF <- hIsEOF stdin
        if inEOF
                then return ()
                else do
                        line <- getLine
                        print $ sumAB line
                        main

题解：

住在天堂那位生前最擅长的事情就是教我向前看、

住在天堂那位去世后我最擅长的事情是让我自己向前看。

Ac代码：

#include<stdio.h>#include<string.h>using namespace std;int main(){    int a,b;    while(~scanf("%d%d",&a,&b)    {    printf("%d\n",a+b);    }}