在一个数组中实现两个堆栈

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4-7 在一个数组中实现两个堆栈   (20分)

本题要求在一个数组中实现两个堆栈。

函数接口定义:

Stack CreateStack( int MaxSize );bool Push( Stack S, ElementType X, int Tag );ElementType Pop( Stack S, int Tag );

其中Tag是堆栈编号,取1或2;MaxSize堆栈数组的规模;Stack结构定义如下:

typedef int Position;struct SNode {    ElementType *Data;    Position Top1, Top2;    int MaxSize;};typedef struct SNode *Stack;

注意:如果堆栈已满,Push函数必须输出“Stack Full”并且返回false;如果某堆栈是空的,则Pop函数必须输出“Stack Tag Empty”(其中Tag是该堆栈的编号),并且返回ERROR。

裁判测试程序样例:

#include <stdio.h>#include <stdlib.h>#define ERROR 1e8typedef int ElementType;typedef enum { push, pop, end } Operation;typedef enum { false, true } bool;typedef int Position;struct SNode {    ElementType *Data;    Position Top1, Top2;    int MaxSize;};typedef struct SNode *Stack;Stack CreateStack( int MaxSize );bool Push( Stack S, ElementType X, int Tag );ElementType Pop( Stack S, int Tag );Operation GetOp();  /* details omitted */void PrintStack( Stack S, int Tag ); /* details omitted */int main(){    int N, Tag, X;    Stack S;    int done = 0;    scanf("%d", &N);    S = CreateStack(N);    while ( !done ) {        switch( GetOp() ) {        case push:             scanf("%d %d", &Tag, &X);            if (!Push(S, X, Tag)) printf("Stack %d is Full!\n", Tag);            break;        case pop:            scanf("%d", &Tag);            X = Pop(S, Tag);            if ( X==ERROR ) printf("Stack %d is Empty!\n", Tag);            break;        case end:            PrintStack(S, 1);            PrintStack(S, 2);            done = 1;            break;        }    }    return 0;}/* 你的代码将被嵌在这里 */

输入样例:

5Push 1 1Pop 2Push 2 11Push 1 2Push 2 12Pop 1Push 2 13Push 2 14Push 1 3Pop 2End

输出样例:

Stack 2 EmptyStack 2 is Empty!Stack FullStack 1 is Full!Pop from Stack 1: 1

Pop from Stack 2: 13 12 11

//两个栈相向而行
Stack CreateStack( int MaxSize ){    Stack p=(Stack)malloc(sizeof(struct SNode));    p->Data=(ElementType*)malloc(sizeof(int)*MaxSize);    p->Top1=-1;    p->Top2=MaxSize;    p->MaxSize=MaxSize;    return p;}bool Push( Stack S, ElementType X, int Tag ){    if(S->Top2-S->Top1==1){        printf("Stack Full\n");        return false;    }    if(Tag==1){        S->Data[++(S->Top1)]=X;        return true;    }    else{        S->Data[--(S->Top2)]=X;        return true;    }}ElementType Pop( Stack S, int Tag ){      if(Tag==1){        if(S->Top1==-1){            printf("Stack %d Empty\n",Tag);            return ERROR;        }        return S->Data[(S->Top1)--];    }    else{        if(S->Top2==S->MaxSize){            printf("Stack %d Empty\n",Tag);            return ERROR;        }        return S->Data[(S->Top2)++];    }}


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