android获得字符串数组中出现次数最多的字符串

  public static String findMaxString(String[] arr) {        Map<Integer, String> map = new HashMap<Integer, String>();        for (int i = 0; i < arr.length - 1; i++) {            int count = 0;            String temp = null;            for (int j = i + 1; j < arr.length; j++) {                if (arr[i].equals(arr[j])) {                    count++;                    temp = arr[i];                }            }//从第一个字符开始比较，每次比较完成后，将相同字符的数目和字符储存在map中            map.put(count + 1, temp);        }        int[] countArr = new int[map.size()];        for (int c : map.keySet()) {            for (int i = 0; i < map.size(); i++) {//将map集合的键存储在数组中                countArr[i] = c;            }        }        Arrays.sort(countArr);        int MAXCOUNT = countArr[countArr.length - 1];        String maxvalue = map.get(MAXCOUNT);        String[] maxString = new String[MAXCOUNT];        for (int i = 0; i < MAXCOUNT; i++) {            maxString[i] = maxvalue;        }        return maxvalue;    }