PAT 乙级 1058 选择题(20) Java版

由于之前此题java超时，最后曲线救国，刷了无数题之后，找到了一个java快速io

源码先贴出来 已ac

import java.io.BufferedReader;import java.io.IOException;import java.io.InputStreamReader;import java.io.StreamTokenizer;public class Main {    static StreamTokenizer in = new StreamTokenizer(new BufferedReader(new InputStreamReader(System.in)));    static int nextInt() throws IOException{in.nextToken(); return (int) in.nval;}    static String next() throws IOException{in.nextToken(); return in.sval;}    public static void main(String[] args) throws IOException {        int gradePb[], gradePs = 0, n, m, wrongCnt[];        int maxCnt = 0;        String str, ansStr[];        StringBuilder sb = new StringBuilder();        char ch;        n = nextInt();        m = nextInt();        gradePb = new int[m];        wrongCnt = new int[m];        ansStr = new  String[m];        int a, b, c, ttemp;        for(int i = 0; i < m; i++)        {            a = nextInt();            b = nextInt();            c = nextInt();            ttemp = c;            sb.append(c);            while(ttemp-- > 0)            {                str = next();                sb.append(str);            }          ansStr[i] = sb.toString();          gradePb[i] = a;          sb.delete(0, sb.length());        }        for(int i = 0; i < n; i++)        {                   for(int j = 0; j < m; j++)            {                in.nextToken();                while((char)in.ttype != ')')                {                    if(in.ttype == StreamTokenizer.TT_NUMBER) sb.append((int)in.nval);                    if(in.ttype == StreamTokenizer.TT_WORD) sb.append(in.sval);                    in.nextToken();                }                str = sb.toString();                sb.delete(0, sb.length());                if(ansStr[j].equals(str)) gradePs+=gradePb[j];                else wrongCnt[j]++;            }            System.out.println(gradePs);            gradePs = 0;        }        for(int i = 0; i < m; i++)        {            if(maxCnt < wrongCnt[i]) maxCnt = wrongCnt[i];        }        if(maxCnt > 0)        {            System.out.print(maxCnt);            for(int i = 1; i <= m; i++)            {                if(wrongCnt[i-1] == maxCnt)                    System.out.print(" "+i);            }        }        else        {            System.out.print("Too simple");        }//      System.out.println("all time is :"+(end-start)+"ms");    }}

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思悟

提交次数就不说了。。。简直要怀疑人生了。用尽各种javaIO的操作，优化再优化，无奈，java无法像c/c++可以非常便捷轻快的边读取数据边处理，但是不得不说javaIO的操作还是很舒服的，如果没有这么大时间消耗的话会更好吧！