Leetcode 114. Flatten Binary Tree to Linked List 二叉树到链表 解题报告
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1 解题思想
这道题,其实也就是把二叉树转变成一个链表他题目里面要求的原地,其实用一个List暂存下引用也ok
2 原题
Given a binary tree, flatten it to a linked list in-place. For example,Given 1 / \ 2 5 / \ \ 3 4 6The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6
3 AC解
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ /** * 使用队列来记录遍历顺序,然后改写就好。 */public class Solution { List<TreeNode> orders=new ArrayList<TreeNode>(); public void dfs(TreeNode root){ orders.add(root); if(root.left!=null) dfs(root.left); if(root.right!=null) dfs(root.right); } public void flatten(TreeNode root) { if(root==null) return ; dfs(root); TreeNode last=root; root.left=null; root.right=null; for(int i=1;i<orders.size();i++){ root.right=orders.get(i); root=orders.get(i); root.left=null; root.right=null; } }}
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