【LeetCode】Flatten Binary Tree to Linked List 解题报告
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【LeetCode】Flatten Binary Tree to Linked List 解题报告
标签(空格分隔): LeetCode
题目地址:https://leetcode.com/problems/flatten-binary-tree-to-linked-list/#/description
题目描述:
Given a binary tree, flatten it to a linked list in-place.
For example,
Given
1 / \ 2 5 / \ \ 3 4 6
The flattened tree should look like:
1 \ 2 \ 3 \ 4 \ 5 \ 6
Ways
这个题不是很好想,这个方法是把所有的节点和其左孩子打断,然后递归把这个左节点转换为自己的右节点。
1 / \ 2 5 / \ \ 3 4 6
变成:
1 \ 2 5 \ \ 3 4 6
2是root,3是left,4是right。修改成下面这样:
再变成:
1 \ 2 5 \ \ 3 6 \ 4
再变成:
1 \ 2 \ 3 \ 4 \ 5 \ 6
代码:
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */public class Solution { public void flatten(TreeNode root) { if(root == null){ return; } TreeNode left = root.left; TreeNode right = root.right; root.left = null; flatten(left); flatten(right); root.right = left; TreeNode cur = root; while(cur.right != null){ cur = cur.right; } cur.right = right; }}
Date
2017 年 4 月 19 日
0 0
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