HDU ACM 11 2055 An easy problem

确实很easy

#include <iostream>  using namespace std;  int main()  {      int Lu[150];      for (int i = 65; i < 91; i++)          Lu[i] = i - 64;      for (int i = 97; i < 123; i++)          Lu[i] = -(i - 96);      int Yi, n;      char Hui;      cin >> n;      while (n--)      {          cin >> Hui >> Yi;          cout << (Lu[Hui] + Yi) << endl;      }      return 0;  }