poj-1579-Function Run Fun【思维】
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题目链接:
Function Run Fun
Time Limit: 1000MS Memory Limit: 10000KTotal Submissions: 18356 Accepted: 9386
Description
We all love recursion! Don't we?
Consider a three-parameter recursive function w(a, b, c):
if a <= 0 or b <= 0 or c <= 0, then w(a, b, c) returns:
1
if a > 20 or b > 20 or c > 20, then w(a, b, c) returns:
w(20, 20, 20)
if a < b and b < c, then w(a, b, c) returns:
w(a, b, c-1) + w(a, b-1, c-1) - w(a, b-1, c)
otherwise it returns:
w(a-1, b, c) + w(a-1, b-1, c) + w(a-1, b, c-1) - w(a-1, b-1, c-1)
This is an easy function to implement. The problem is, if implemented directly, for moderate values of a, b and c (for example, a = 15, b = 15, c = 15), the program takes hours to run because of the massive recursion.
Consider a three-parameter recursive function w(a, b, c):
if a <= 0 or b <= 0 or c <= 0, then w(a, b, c) returns:
1
if a > 20 or b > 20 or c > 20, then w(a, b, c) returns:
w(20, 20, 20)
if a < b and b < c, then w(a, b, c) returns:
w(a, b, c-1) + w(a, b-1, c-1) - w(a, b-1, c)
otherwise it returns:
w(a-1, b, c) + w(a-1, b-1, c) + w(a-1, b, c-1) - w(a-1, b-1, c-1)
This is an easy function to implement. The problem is, if implemented directly, for moderate values of a, b and c (for example, a = 15, b = 15, c = 15), the program takes hours to run because of the massive recursion.
Input
The input for your program will be a series of integer triples, one per line, until the end-of-file flag of -1 -1 -1. Using the above technique, you are to calculate w(a, b, c) efficiently and print the result.
Output
Print the value for w(a,b,c) for each triple.
Sample Input
1 1 12 2 210 4 650 50 50-1 7 18-1 -1 -1
Sample Output
w(1, 1, 1) = 2w(2, 2, 2) = 4w(10, 4, 6) = 523w(50, 50, 50) = 1048576w(-1, 7, 18) = 1
#include<cstdio>#include<algorithm>#include<cstring>#define LL long longusing namespace std;LL a,b,c;LL w[30][30][30];int main(){for(int i=0;i<=20;i++){for(int j=0;j<=20;j++){for(int k=0;k<=20;k++){if(!i||!j||!k)w[i][j][k]=1;else if(i<j&&j<k)w[i][j][k]=w[i][j][k-1]+w[i][j-1][k-1]-w[i][j-1][k];elsew[i][j][k]=w[i-1][j][k]+w[i-1][j-1][k]+w[i-1][j][k-1]-w[i-1][j-1][k-1];}}}while(~scanf("%lld%lld%lld",&a,&b,&c)){if(a==-1&&b==-1&&c==-1)break;LL ans;if(a<=0||b<=0||c<=0)ans=1;else if(a>20||b>20||c>20)ans=w[20][20][20];elseans=w[a][b][c];printf("w(%lld, %lld, %lld) = %lld\n",a,b,c,ans);}return 0;}
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