LeetCode342. Power of Four 简单解法
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题目要求:
Given an integer (signed 32 bits), write a function to check whether it is a power of 4.
Example:
Given num = 16, return true. Given num = 5, return false.
Follow up: Could you solve it without loops/recursion?
public class solution_new {public boolean isPowerOfFour(int num) {if(num > 0 && (num & 0x55555555) != 0 && (num & num - 1) == 0) return true;return false;}}判断num 是否大于0;然后进行二进制奇数位的选取;最后要除去2的幂数.
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