HDU 1037 Keep on Truckin'(水题)

题目传送门:HDU 1037 Keep on Truckin'

题目大意: 给出三个数,若都 >= 168则输出 NO CRASH， 否则 输出第一个小于168的数(小于168的数中最小的, 比如111, 90, 120，就输出CRASH 90);

题解:简单地用sort排个序, 然后用num[0]（三个数中最小的）与168进行比较.

#include<iostream>#include<cstdlib>#include<cstdio>#include<algorithm>#include<cmath>#include<map>#include<stack>#include<queue>#include<ctime>#include<cstring>#include<string>#define LL __int64#define INF 0x3f3f3f3f3fusing namespace std;int main(){int i, j, k, n, num[4];while(~scanf("%d%d%d", &num[0], &num[1], &num[2])){sort(num, num+3);if(num[0]>=168) printf("NO CRASH\n");elseprintf("CRASH %d\n", num[0]);}return 0;}