GPS坐标转换为百度坐标 js封装

来源：互联网发布：spss19.0数据分析教程编辑：程序博客网时间：2024/04/30 04:59

前言

BMap.Convertor在坐标转换上有数量限制，这点在实际的项目中受限。参考网上一些文档，封装了下面js版的坐标转换工具pointtransfertools.js。经测试，误差在可容忍范围之内。

下载js

pointtransfertools.js：http://download.csdn.net/detail/u010989191/9668840

pointtransfertools.js：

/***   地图位置计算工具(将GPS坐标转换成百度地图坐标)*    参考文档：http://bbs.lbsyun.baidu.com/forum.php?mod=viewthread&tid=10923&qq-pf-to=pcqq.group**    使用示例：批量转换坐标位置*    *    var transferedData = GpsToBaiduPoints(prePoints);*    $.each(transferedData,function(index,point){*       console.log(point);*    });**-------------------以下是提供的一个简单的访问接口-------------------------*    参数: points:new BMap.Point(lng,lat)的集合*    返回值:resultPoints:转换后 BMap.point点集*    function GpsToBaiduPoints(points){*        var resultPoints = [];*        $.each(points,function(index,point){*            //世界大地坐标转为百度坐标*            var _t = wgs2bd(point.lat,point.lng);*            var _BPoint = new BMap.Point(_t[1], _t[0]);*            resultPoints.push(_BPoint);*        });*        return resultPoints;*    }*///默认提供一个接口直接调用function GpsToBaiduPoints(points){    var resultPoints = [];    $.each(points,function(index,point){        var _t = wgs2bd(point.lat,point.lng);        var _BPoint = new BMap.Point(_t[1], _t[0]);        resultPoints.push(_BPoint);    });    return resultPoints;}////////////////////////////////////////////////////////转换核心代码//////////////////////////////////////////////////////////var pi = 3.14159265358979324;var a = 6378245.0;var ee = 0.00669342162296594323;var x_pi = 3.14159265358979324*3000.0/180.0;//世界大地坐标转为百度坐标function wgs2bd(lat,lon) {    var wgs2gcjR = wgs2gcj(lat, lon);    var gcj2bdR = gcj2bd(wgs2gcjR[0], wgs2gcjR[1]);    return gcj2bdR;}function gcj2bd(lat,lon) {    var x = lon, y = lat;    var z = Math.sqrt(x * x + y * y) + 0.00002 * Math.sin(y * x_pi);    var theta = Math.atan2(y, x) + 0.000003 * Math.cos(x * x_pi);    var bd_lon = z * Math.cos(theta) + 0.0065;    var bd_lat = z * Math.sin(theta) + 0.006;    var result = [];    result.push(bd_lat);    result.push(bd_lon);    return result;}function bd2gcj(lat,lon) {    var x = lon - 0.0065, y = lat - 0.006;    var z = Math.sqrt(x * x + y * y) - 0.00002 * Math.sin(y * x_pi);    var theta = Math.atan2(y, x) - 0.000003 * Math.cos(x * x_pi);    var gg_lon = z * Math.cos(theta);    var gg_lat = z * Math.sin(theta);    var result = [];    result.push(gg_lat);    result.push(gg_lon);    return result;}function wgs2gcj(lat,lon) {    var dLat = transformLat(lon - 105.0, lat - 35.0);    var dLon = transformLon(lon - 105.0, lat - 35.0);    var radLat = lat / 180.0 * pi;    var magic = Math.sin(radLat);    magic = 1 - ee * magic * magic;    var sqrtMagic = Math.sqrt(magic);    dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);    dLon = (dLon * 180.0) / (a / sqrtMagic * Math.cos(radLat) * pi);    var mgLat = lat + dLat;    var mgLon = lon + dLon;    var result = [];    result.push(mgLat);    result.push(mgLon);    return result;}function transformLat(lat,lon) {    var ret = -100.0 + 2.0 * lat + 3.0 * lon + 0.2 * lon * lon + 0.1 * lat * lon + 0.2 * Math.sqrt(Math.abs(lat));    ret += (20.0 * Math.sin(6.0 * lat * pi) + 20.0 * Math.sin(2.0 * lat * pi)) * 2.0 / 3.0;    ret += (20.0 * Math.sin(lon * pi) + 40.0 * Math.sin(lon / 3.0 * pi)) * 2.0 / 3.0;    ret += (160.0 * Math.sin(lon / 12.0 * pi) + 320 * Math.sin(lon * pi  / 30.0)) * 2.0 / 3.0;    return ret;}function transformLon(lat,lon) {    var ret = 300.0 + lat + 2.0 * lon + 0.1 * lat * lat + 0.1 * lat * lon + 0.1 * Math.sqrt(Math.abs(lat));    ret += (20.0 * Math.sin(6.0 * lat * pi) + 20.0 * Math.sin(2.0 * lat * pi)) * 2.0 / 3.0;    ret += (20.0 * Math.sin(lat * pi) + 40.0 * Math.sin(lat / 3.0 * pi)) * 2.0 / 3.0;    ret += (150.0 * Math.sin(lat / 12.0 * pi) + 300.0 * Math.sin(lat / 30.0 * pi)) * 2.0 / 3.0;    return ret;}

实际测试效果

这里写图片描述

参考资料：
http://bbs.lbsyun.baidu.com/forum.php?mod=viewthread&tid=10923&qq-pf-to=pcqq.group

0 0