Java中List的排序

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第一种方法，就是list中对象实现Comparable接口，代码如下：

public class Person implements Comparable<Person> {    private String name;    private Integer order;    /**     * @return the name     */    public String getName() {        return name;    }    /**     * @param name     *            the name to set     */    public void setName(String name) {        this.name = name;    }    /**     * @return the order     */    public Integer getOrder() {        return order;    }    /**     * @param order     *            the order to set     */    public void setOrder(Integer order) {        this.order = order;    }    @Override    public int compareTo(Person arg0) {        return this.getOrder().compareTo(arg0.getOrder());    }}

public static void main(String[] args) {    List<Person> listA = new ArrayList<Person>();    Person p1 = new Person();    Person p2 = new Person();    Person p3 = new Person();    p1.setName("name1");    p1.setOrder(1);    p2.setName("name2");    p2.setOrder(2);    p3.setName("name3");    p3.setOrder(3);    listA.add(p2);    listA.add(p1);    listA.add(p3);    Collections.sort(listA);    for (Person p : listA) {        System.out.println(p.getName());    }}

第二种方法，就是在重载Collections.sort方法，代码如下：

public class Person {    private String name;    private Integer order;    /**     * @return the name     */    public String getName() {        return name;    }    /**     * @param name     *            the name to set     */    public void setName(String name) {        this.name = name;    }    /**     * @return the order     */    public Integer getOrder() {        return order;    }    /**     * @param order     *            the order to set     */    public void setOrder(Integer order) {        this.order = order;    }}

public static void main(String[] args) {        List<Person> listA = new ArrayList<Person>();        Person p1 = new Person();        Person p2 = new Person();        Person p3 = new Person();        p1.setName("name1");        p1.setOrder(1);        p2.setName("name2");        p2.setOrder(2);        p3.setName("name3");        p3.setOrder(3);        listA.add(p2);        listA.add(p1);        listA.add(p3);        Collections.sort(listA, new Comparator<Person>() {            public int compare(Person arg0, Person arg1) {                return arg0.getOrder().compareTo(arg1.getOrder());            }        });        for (Person p : listA) {            System.out.println(p.getName());        }    }

两次执行的结果都是：

name1

name2

name3

原文地址：http://www.cnblogs.com/wentiertong/archive/2011/03/07/1973698.html

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