HDU 5935 Car (模拟)

Car

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 590 Accepted Submission(s): 205

Problem Description
Ruins is driving a car to participating in a programming contest. As on a very tight schedule, he will drive the car without any slow down, so the speed of the car is non-decrease real number.

Of course, his speeding caught the attention of the traffic police. Police record N positions of Ruins without time mark, the only thing they know is every position is recorded at an integer time point and Ruins started at 0.

Now they want to know the minimum time that Ruins used to pass the last position.

Input
First line contains an integer T, which indicates the number of test cases.

Every test case begins with an integers N, which is the number of the recorded positions.

The second line contains N numbers a1, a2, ⋯, aN, indicating the recorded positions.

Limits
1≤T≤100
1≤N≤105
0

#include "cstring"#include "cstdio"#include "string.h"#include "iostream"#include "cmath"#include "algorithm"using namespace std;#define MAX 100005#define exp 0.00000000001int main(){    int t;    scanf("%d",&t);    int cas=1;    while(t--)    {        int n;        scanf("%d",&n);        int a[MAX];        for(int i=1;i<=n;i++)            scanf("%d",&a[i]);        a[0]=0;        int totaltime=1;        double vmax=(double)(a[n]-a[n-1]);        for(int i=n-1;i>=1;i--)        {            double dis=1.0*(a[i]-a[i-1]);            int time=dis/vmax;            totaltime+=time;            //if(time*vmax!=dis)            if(dis/time!=vmax)            {                totaltime++;                vmax=dis/(time+1);            }            else                vmax=dis/time;        }        printf("Case #%d: %d\n",cas++,totaltime);    }}