【HDU 5980 Find Small A】+ 2016ACM/ICPC亚洲区大连站-重现赛（感谢大连海事大学）

Find Small A
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 324 Accepted Submission(s): 162

Problem Description
As is known to all,the ASCII of character ‘a’ is 97. Now,find out how many character ‘a’ in a group of given numbers. Please note that the numbers here are given by 32 bits’ integers in the computer.That means,1digit represents 4 characters(one character is represented by 8 bits’ binary digits).

Input
The input contains a set of test data.The first number is one positive integer N (1≤N≤100),and then N positive integersai (1≤ ai≤2^32 - 1) follow

Output
Output one line,including an integer representing the number of ‘a’ in the group of given numbers.

Sample Input

3
97 24929 100

Sample Output

3

Source
2016ACM/ICPC亚洲区大连站-重现赛（感谢大连海事大学）

每个数的二进制位每 8 位 为一个字符，有多少个等于’a’的ASCII字符～

AC代码：

#include<bits/stdc++.h>int pa[33];int main(){    int n,a,nl,ans;    while(scanf("%d",&n) != EOF){        ans = 0;        while(n--){            memset(pa,0,sizeof(pa));            scanf("%d",&a);            nl = 0;        while(a){            pa[++nl] = a & 1;            a >>= 1;        }        for(int i = 1 ; i <= nl; i += 8){            int sum = 0,p = 1;            for(int j = i ; j <= i + 7 ; j++){                sum += p * pa[j];                p <<= 1;            }            if(sum == 97) ans++;        }        }        printf("%d\n",ans);    }    return 0;}