Let the Balloon Rise 也是字符串出现最大次数。
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Let the Balloon Rise
Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64uDescription
Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favorite time is guessing the most popular problem. When the contest is over, they will count the balloons of each color and find the result.
This year, they decide to leave this lovely job to you.
This year, they decide to leave this lovely job to you.
Input
Input contains multiple test cases. Each test case starts with a number N (0 < N <= 1000) -- the total number of balloons distributed. The next N lines contain one color each. The color of a balloon is a string of up to 15 lower-case letters.
A test case with N = 0 terminates the input and this test case is not to be processed.
A test case with N = 0 terminates the input and this test case is not to be processed.
Output
For each case, print the color of balloon for the most popular problem on a single line. It is guaranteed that there is a unique solution for each test case.
Sample Input
5greenredblueredred3pinkorangepink0
Sample Output
redpink
由于数据范围小,所以可以直接双for,进行比较,然后count++,找到出现次数最多的字符串。
#include<stdio.h>#include<string.h>char s[1000][20];int main(){ int n; while(scanf("%d",&n)!=EOF&&n) { char a[20]; for(int i=0;i<n;i++) scanf("%s",s[i]); int maxn=-1; for(int i=0;i<n;i++) { int k=1; for(int j=i+1;j<n;j++) { if(strcmp(s[i],s[j])==0) k++; } if(k>maxn) { maxn=k; strcpy(a,s[i]); } } printf("%s\n",a); }return 0;}
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