HDU 1004.Let the Balloon Rise【找出出现次数最多的字符串】

Let the Balloon Rise

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 98469    Accepted Submission(s): 37708

Problem Description

Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favorite time is guessing the most popular problem. When the contest is over, they will count the balloons of each color and find the result.

This year, they decide to leave this lovely job to you. 

 

Input

Input contains multiple test cases. Each test case starts with a number N (0 < N <= 1000) -- the total number of balloons distributed. The next N lines contain one color each. The color of a balloon is a string of up to 15 lower-case letters.

A test case with N = 0 terminates the input and this test case is not to be processed.

 

Output

For each case, print the color of balloon for the most popular problem on a single line. It is guaranteed that there is a unique solution for each test case.

 

Sample Input

5greenredblueredred3pinkorangepink0

 

Sample Output

redpink

 

总结：

    本题题意很清楚，就是【找出出现次数最多的字符串】。

1.首先要注意的是，涉及到字符串的题目，都要加#include<string.h>这个头文件（要加.h哦）；

2.把出现的各个颜色用【二维数组】存起来，并且对每个颜色的出现次数都要做一个统计用cnt[1000]；

3.第一遍输入时，要先输入第一个颜色，后面每输入一个颜色，都要与之前的i-1个作比较，如果出现相同的，cnt[i]++；

4.最后一步，求出最大的cnt[i]，通过遍历加一个if(>)的条件，求出max，同时用position记录出其位置。 

5.用scanf、printf输出字符串时用“%s”。

代码如下： 

#include <iostream>

#include <stdio.h>
#include <string.h>
using namespace std;


int main()
{
    char color[1000][16];
    int n, i, j, cnt[1000];
    int xmax, pos;
    while(scanf("%d", &n) != EOF)
    {
        if(n)
        {
            cnt[0] = 0;
            scanf("%s", color[0]);
            for(i=1; i<n; i++)
            {
                cnt[i] = 0;
                scanf("%s", color[i]);
                for(j=0; j<i-1; j++)
                {
                    if(strcmp(color[i],color[j])==0)
                        cnt[i] += 1;
                }
            }
            xmax = 0;
            pos = 0;
            for(i=1; i<n; i++)
            {
                if(xmax < cnt[i])
                {
                    xmax = cnt[i];
                    pos = i;
                }
            }
            printf("%s\n",&color[pos]);
        }
    }
    return 0;
}