[LeetCode]Sum Root to Leaf Numbers

来源:互联网 发布:淘宝上的面膜能不能买 编辑:程序博客网 时间:2024/05/29 07:50

Question
Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.

An example is the root-to-leaf path 1->2->3 which represents the number 123.

Find the total sum of all root-to-leaf numbers.

For example,

    1   / \  2   3

The root-to-leaf path 1->2 represents the number 12.
The root-to-leaf path 1->3 represents the number 13.

Return the sum = 12 + 13 = 25.


本题难度Medium。

DFS

【复杂度】
时间 O(N) 空间 O(1)

【思路】
这道题并不难,从上而下地进行递推累加,然后返回其累加值。

【注意】
叶子节点是其左右子树都为null。只有一个子树为null的不是叶子节点!

【代码】

/** * Definition for a binary tree node. * public class TreeNode { *     int val; *     TreeNode left; *     TreeNode right; *     TreeNode(int x) { val = x; } * } */public class Solution {    public int sumNumbers(TreeNode root) {        //invariant        return helper(root,0);    }    private int helper(TreeNode root,int pre){        //base case        if(root==null)            return 0;        if(root.left==null&&root.right==null)            return pre*10+root.val;        return helper(root.left,pre*10+root.val)+helper(root.right,pre*10+root.val);    }}
0 0
原创粉丝点击