【玲珑学院 1057 - Private Value】+ map

1057 - Private Value

Time Limit：1s Memory Limit：128MByte

Submissions：511Solved：165
DESCRIPTION

The “private value” is the value that occurs, but most infrequent.

An array of integers is given, and you need print the private values of the array.

Please notice that, there might be several private values, and you need print them in increasing order.

INPUT
The first line is an integer T(1 <= T <= 4), indicating the number of test cases.
For each case, the first line contains an integer n (n <= 100000).
The second line contains n integers a_i (0 <= a_i <= 10^9),
OUTPUT
For each case, print all private values in increasing order in a line.
SAMPLE INPUT
2
7
1 1 2 2 3 3 3
5
5 3 2 4 1
SAMPLE OUTPUT
1 2
1 2 3 4 5

map～映射～～

#include<cstdio>#include<map>#include<algorithm>using namespace std;const int MAXN = 100010;map <int,int> m;int ma[MAXN];int main(){    int T,n;    scanf("%d",&T);    while(T--){        scanf("%d",&n);        for(int i = 1 ; i <= n ; i++){            scanf("%d",&ma[i]);            m[ma[i]]++;        }        sort(ma + 1, ma + 1 + n);        int minn = 1e8;        for(int i = 1 ; i <= n ; i++)            minn = min(minn,m[ma[i]]);        int ok = 0;        for(int i = 1 ; i <= n ; i++){            if(m[ma[i]] == minn){                if(ok) printf(" ");                printf("%d",ma[i]);                ok = 1;            }            m[ma[i]] = 0; // 每次用过后清空         }        printf("\n");    }    return 0;}