Construct Binary Tree from Preorder and Inorder Traversal ---LeetCode

https://leetcode.com/problems/construct-binary-tree-from-inorder-and-postorder-traversal/

解题思路：

由于先序遍历（DLR）可以知道根节点的位置，而中序遍历（LDR）可以知道左子树右子树的位置，就可以用递归来实现。记住并理解递归的参数。

举个例子：
preorder: [7, 10, 4, 3, 1, 2, 8, 11]
inorder: [4, 10, 3, 1, 7, 11, 8, 2]

示意图：

/** * Definition for a binary tree node. * public class TreeNode { *     int val; *     TreeNode left; *     TreeNode right; *     TreeNode(int x) { val = x; } * } */public class Solution {    public TreeNode buildTree(int[] preorder, int[] inorder) {        if (preorder == null || inorder == null) return null;        HashMap<Integer, Integer> map = new HashMap<>();        for (int i=0; i<inorder.length; i++)            map.put(inorder[i], i);        return helper(preorder, 0, preorder.length - 1, inorder, 0, inorder.length - 1, map);    }    public TreeNode helper(int[] preorder, int preL, int preR, int[] inorder, int inL, int inR, HashMap<Integer, Integer> map) {        if (preL > preR || inL > inR) return null;        TreeNode root = new TreeNode(preorder[preL]);        int index = map.get(root.val);        root.left  = helper(preorder, preL + 1, index - inL + preL, inorder, inL, index - 1, map);        root.right = helper(preorder, index - inL + preL + 1, preR, inorder, index + 1, inR, map);        return root;    }}