16. 3Sum Closest leetcode(array)
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- 3Sum Closest
For example, given array S = {-1 2 1 -4}, and target = 1.
The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
同15的3sum类似
int threeSumClosest(vector<int>& nums, int target) { vector<vector<int> > ret; int size = nums.size(); sort(nums.begin(), nums.end()); int sum = nums[0]+nums[1]+nums[size-1]; int minDis = sum - target; for(int i = 0; i < size; i++) { int j = i + 1; int k = size -1; while(j<k) { sum = nums[i]+nums[j]+nums[k]; if(abs(sum - target) < abs(minDis)) //注意这部分在这里,不构成以下的if-else,无语。。。。。。 { minDis = sum - target; } //minDis = sum - target; if(sum == target)//增加这部分处理,是对于{1,2,3,4,5,6,7} target=10,这种一旦找到1,2,7三个数,则不用继续遍历,继续 { return target; } else if(sum > target) { k--; } else { j++; } } } return minDis + target; }
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