A - Broken Clock

A - Broken Clock

Crawling in process...Crawling failedTime Limit:1000MS    Memory Limit:262144KB    64bit IO Format:%I64d & %I64u

SubmitStatusPractice CodeForces 722A uDebug

Description

Input

Output

Sample Input

Sample Output

Hint

Description

You are given a broken clock. You know, that it is supposed to show time in 12- or 24-hoursHH:MM format. In 12-hours format hours change from1 to12, while in 24-hours it changes from0 to23. In both formats minutes change from0 to59.

You are given a time in format HH:MM that is currently displayed on the broken clock. Your goal is to change minimum number of digits in order to make clocks display the correct time in the given format.

For example, if 00:99 is displayed, it is enough to replace the second9 with3 in order to get00:39 that is a correct time in 24-hours format. However, to make00:99 correct in 12-hours format, one has to change at least two digits. Additionally to the first change one can replace the second0 with1 and obtain01:39.

Input

The first line of the input contains one integer 12 or24, that denote 12-hours or 24-hours format respectively.

The second line contains the time in format HH:MM, that is currently displayed on the clock. First two characters stand for the hours, while next two show the minutes.

Output

The only line of the output should contain the time in format HH:MM that is a correct time in the given format. It should differ from the original in as few positions as possible. If there are many optimal solutions you can print any of them.

Sample Input

Input

2417:30

Output

17:30

Input

1217:30

Output

07:30

Input

2499:99

Output

09:09

题意
12小时制的话，时钟是从1开始到12的。
24小时制的话，时钟是从0开始到23的
然后给你一个小时制度，然后再给你一个时间，问你这个时间是否合法，如果不合法的话，你需要修改最少的数字，使得这个时间合法 。

#include<stdio.h>int main(){    int n;    while(scanf("%d",&n)!=-1)    {        char a[100];        scanf("%s",a);         int we=0,ni=0;           we=(a[0]-'0')*10+(a[1]-'0');           ni=(a[3]-'0')*10+(a[4]-'0');        if(n==12)        {            if (we >=1 && we<= 12);            else            {if(we%10==0)            {                we=10;            }                else we %= 10;            }if (ni >= 0 && ni <= 59);else ni%= 10;        }        else        {           if (we >= 0 && we<= 23);else we %= 10;if (ni >= 0 && ni <= 59);else ni%= 10;        }        if(we<=9&&ni<=9)        printf("0%d:0%d\n",we,ni);       else if(we<=9&&ni>=10)            printf("0%d:%d\n",we,ni);          else  if(we>=10&&ni<=9)        printf("%d:0%d\n",we,ni);        else        printf("%d:%d\n",we,ni);    }}