HDU 2012 素数判定 (Java)

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素数判定

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 129528    Accepted Submission(s): 45422


Problem Description
对于表达式n^2+n+41,当n在(x,y)范围内取整数值时(包括x,y)(-39<=x<y<=50),判定该表达式的值是否都为素数。
 

Input
输入数据有多组,每组占一行,由两个整数x,y组成,当x=0,y=0时,表示输入结束,该行不做处理。
 

Output
对于每个给定范围内的取值,如果表达式的值都为素数,则输出"OK",否则请输出“Sorry”,每组输出占一行。
 

Sample Input
0 10 0
 

Sample Output
OK
 

Author
lcy
 

Source
C语言程序设计练习(二)
 

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import java.util.Scanner;public class Main {     public static void main(String args[])     {    Scanner in = new Scanner(System.in);    while(in.hasNext())    {    int a = in.nextInt();    int b = in.nextInt();    if(a == 0 && b == 0)    {    break;    }    int flag = 0;    for( int i = a; i<= b; i++)    {    int ans = i * i + i + 41;    if(prim(ans) == 0)    {    flag = 1;    }    }    if (flag == 1)    System.out.println("Sorry");    else    {    System.out.println("OK");    }    }     }     public static int prim(int n)     {     for( int i = 2; i * i <= n; i++)     {     if(n%i==0)     return 0;     }     return 1;     }}


 
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