leetcode 453 Minimum Moves to Equal Array Elements C++
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这道题之后养成了看tag的习惯，tag真的能给你很大的帮助
这道题的tag的math，那应该是有数学方法。
把其他的数字+1，相当于把最大的数字-1.
所以只要算所有数字和最小数字的差的累加和就可以了
int minMoves(vector<int>& nums) { int count = 0; int min = nums[0]; for (int i:nums) min = min < i ? min : i; for (int i:nums) count += i - min; return count; } 0 0
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