Leetcode-453. Minimum Moves to Equal Array Elements

前言：为了后续的实习面试，开始疯狂刷题，非常欢迎志同道合的朋友一起交流。因为时间比较紧张，目前的规划是先过一遍，写出能想到的最优算法，第二遍再考虑最优或者较优的方法。如有错误欢迎指正。博主首发CSDN，mcf171专栏。

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Given a non-empty integer array of size n, find the minimum number of moves required to make all array elements equal, where a move is incrementing n - 1 elements by 1.

Example:

Input:[1,2,3]Output:3Explanation:Only three moves are needed (remember each move increments two elements):[1,2,3]  =>  [2,3,3]  =>  [3,4,3]  =>  [4,4,4]

这个题目其实就是每次每个数只可以减1，然后求最小步数。时间复杂度O(n)遍历一次即可。Your runtime beats 67.89% of java submissions.

public class Solution {    public int minMoves(int[] nums) {if(nums.length == 0) return 0;int minNumber = nums[0],result = 0;        for(int i = 0 ; i < nums.length ; i++){int item = nums[i];if(item < minNumber) {result += (minNumber - item) * i;minNumber = item; }else result += item - minNumber;} return result;    }}