找出链表的第一个公共结点

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两个单向链表,找出它们的第一个公共结点。

思想:采用先后指针

unsigned int GetListLength(ListNode* pHead);


ListNode* FindFirstCommonNode(ListNode *pHead1, ListNode *pHead2) {
// 得到两个链表的长度
unsigned int nLength1 = GetListLength(pHead1);
unsigned int nLength2 = GetListLength(pHead2);
int nLengthDif = nLength1 - nLength2;


ListNode* pListHeadLong = pHead1;
ListNode* pListHeadShort = pHead2;
if (nLength2 > nLength1) {
pListHeadLong = pHead2;
pListHeadShort = pHead1;
nLengthDif = nLength2 - nLength1;
}


// 先在长链表上走几步,再同时在两个链表上遍历
for (int i = 0; i < nLengthDif; ++i)
pListHeadLong = pListHeadLong->m_pNext;


while ((pListHeadLong != NULL) && (pListHeadShort != NULL)
&& (pListHeadLong != pListHeadShort)) {
pListHeadLong = pListHeadLong->m_pNext;
pListHeadShort = pListHeadShort->m_pNext;
}


// 得到第一个公共结点
ListNode* pFisrtCommonNode = pListHeadLong;


return pFisrtCommonNode;
}


unsigned int GetListLength(ListNode* pHead) {
unsigned int nLength = 0;
ListNode* pNode = pHead;
while (pNode != NULL) {
++nLength;
pNode = pNode->m_pNext;
}


return nLength;
}

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