Magic Spheres--Codeforce

Carl is a beginner magician. He has a blue, b violet and c orange magic spheres. In one move he can transform two spheres of the same color into one sphere of any other color. To make a spell that has never been seen before, he needs at least x blue, y violet and z orange spheres. Can he get them (possible, in multiple actions)?

Input

The first line of the input contains three integers a, b and c (0 ≤ a, b, c ≤ 1 000 000) — the number of blue, violet and orange spheres that are in the magician's disposal.The second line of the input contains three integers, x, y and z (0 ≤ x, y, z ≤ 1 000 000) — the number of blue, violet and orange spheres that he needs to get.

Output

If the wizard is able to obtain the required numbers of spheres, print "Yes". Otherwise, print "No".

Example
Input

4 4 02 1 2OutputYesInput5 6 12 7 2OutputNoInput3 3 32 2 2OutputYes

Note

In the first sample the wizard has 4 blue and 4 violet spheres. In his first action he can turn two blue spheres into one violet one. After that he will have 2 blue and 5 violet spheres. Then he turns 4 violet spheres into 2 orange spheres and he ends up with 2 blue, 1 violet and 2 orange spheres, which is exactly what he needs.

题意：
给你 黄篮紫三种颜色的东西a b c个 每两个相同颜色的可兑换成一个其他颜色的。 给出三个数字xyz，问你能否使每种颜色的球大于搜给出的数字。
这题蛋碎了一地。 题意没看清，以为是要使abc恰好等于xyz磨蹭了一个多小时。orz。
解题思路：
暴力模拟。

#include<iostream>#include<cstdio>#include<string.h>#include<string>#include<queue>#include<algorithm>#include<vector>using namespace std;int dp[100005][15];int main(){    int a,b,c;    int na,nb,nc;    while(scanf("%d%d%d",&a,&b,&c)!=EOF)    {        int havd=0,need=0;        scanf("%d%d%d",&na,&nb,&nc);        a-=na;        b-=nb;        c-=nc;        a>0?havd+=a/2:need+=a;        b>0?havd+=b/2:need+=b;        c>0?havd+=c/2:need+=c;        //cout<<havd<<""<<need;        if((havd+need)>=0)            puts("YES\n");        else            puts("NO\n");    }    return 0;}