2017_0117

2017-0117

1 ）100以内能被5或7整除的数，每行5个显示出来

#include <stdio.h>

int main()

{

int i,n;

for(i = 1 , n = 0 ;i <= 100 ; i ++)

if ( i % 7 == 0 || i % 5 == 0)

{

printf( " %d\t ", i );

n++;

if ( n%5 == 0)

printf ( " \n ");

}

printf( " \n ");

return 0;

}

 

 

2 e的近似值 1+1/1！+1/2！+...+1/n! 当1/n!  < 1e-5时，条件不成立

 

include<stdio.h>

int main()

 {double sum = 1.0 , d = 1 , j = 1 , e = 1.0 ;

  while ( d >1e-6 ）

  {

    sum *= j ;

     d = 1.0 / sum ;

     e += d;

     j++;

  }

printf( " %f " ,e );

return 0 ;

}