【HDU 3038 How Many Answers Are Wrong】+ 并查集

How Many Answers Are Wrong
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 6663 Accepted Submission(s): 2485

Problem Description
TT and FF are … friends. Uh… very very good friends -__-b

FF is a bad boy, he is always wooing TT to play the following game with him. This is a very humdrum game. To begin with, TT should write down a sequence of integers-_-!!(bored).

Then, FF can choose a continuous subsequence from it(for example the subsequence from the third to the fifth integer inclusively). After that, FF will ask TT what the sum of the subsequence he chose is. The next, TT will answer FF’s question. Then, FF can redo this process. In the end, FF must work out the entire sequence of integers.

Boring~~Boring~~a very very boring game!!! TT doesn’t want to play with FF at all. To punish FF, she often tells FF the wrong answers on purpose.

The bad boy is not a fool man. FF detects some answers are incompatible. Of course, these contradictions make it difficult to calculate the sequence.

However, TT is a nice and lovely girl. She doesn’t have the heart to be hard on FF. To save time, she guarantees that the answers are all right if there is no logical mistakes indeed.

What’s more, if FF finds an answer to be wrong, he will ignore it when judging next answers.

But there will be so many questions that poor FF can’t make sure whether the current answer is right or wrong in a moment. So he decides to write a program to help him with this matter. The program will receive a series of questions from FF together with the answers FF has received from TT. The aim of this program is to find how many answers are wrong. Only by ignoring the wrong answers can FF work out the entire sequence of integers. Poor FF has no time to do this job. And now he is asking for your help~(Why asking trouble for himself~~Bad boy)

Input
Line 1: Two integers, N and M (1 <= N <= 200000, 1 <= M <= 40000). Means TT wrote N integers and FF asked her M questions.

Line 2..M+1: Line i+1 contains three integer: Ai, Bi and Si. Means TT answered FF that the sum from Ai to Bi is Si. It’s guaranteed that 0 < Ai <= Bi <= N.

You can assume that any sum of subsequence is fit in 32-bit integer.

Output
A single line with a integer denotes how many answers are wrong.

Sample Input

10 5
1 10 100
7 10 28
1 3 32
4 6 41
6 6 1

Sample Output

1

Source
2009 Multi-University Training Contest 13 - Host by HIT

题意 ： 给出 N个数，M次询问，每次询问给出左右区间[x，y]，以及区间和d,并判断d是否与之前的回答相矛盾，求回答错误的次数；

思路 ： 把确定关系的x，y并入同一集合，每次把右端点作为根节点，记录每个点到根节点的距离，在一个集合里的[x,y]直接判断，不在一个集合里的并入同一集合

AC代码：

#include<cstdio>int f[200010],s[200010];int bc(int x){    if(x != f[x]){        int p = f[x];        f[x] = bc(p); // 根节点        s[x] += s[p];  // 到根节点的距离    }    return f[x];}int main(){    int N,M,x,y,d;    while(scanf("%d %d",&N,&M) != EOF){        for(int i = 0 ; i <= N; i++)            f[i] = i,s[i] = 0;        int ans = 0;        while(M--){            scanf("%d %d %d",&x,&y,&d);            int fx = bc(--x),fy = bc(y);            if(fx == fy){                if(s[x] - s[y] != d)                    ans++;            }            else{                f[fx] = fy; // 把右端点的根节点的作为新的根节点                s[fx] = s[y] - s[x] + d; // 防止交集情况            }        }        printf("%d\n",ans);    }    return 0;}