334. Increasing Triplet Subsequence**
来源:互联网 发布:时时彩娱乐平台源码 编辑:程序博客网 时间:2024/06/05 05:55
Given an unsorted array return whether an increasing subsequence of length 3 exists or not in the array.
Formally the function should:
Return true if there exists i, j, k
such that arr[i] < arr[j] < arr[k] given 0 ≤ i < j < k ≤ n-1 else return false.
Your algorithm should run in O(n) time complexity and O(1) space complexity.
Examples:
Given [1, 2, 3, 4, 5]
,
return true
.
Given [5, 4, 3, 2, 1]
,
return false
.
public boolean increasingTriplet(int[] nums) { int small = Integer.MAX_VALUE, big = Integer.MAX_VALUE; for(int n:nums){ if(n<=small) {small=n;} else if(n<=big){big=n;} else return true; } return false; }
0 0
- 334. Increasing Triplet Subsequence
- 334. Increasing Triplet Subsequence
- 334. Increasing Triplet Subsequence
- 334. Increasing Triplet Subsequence
- 334. Increasing Triplet Subsequence
- 334. Increasing Triplet Subsequence
- 334. Increasing Triplet Subsequence
- 334. Increasing Triplet Subsequence
- 334. Increasing Triplet Subsequence
- 334. Increasing Triplet Subsequence
- 334. Increasing Triplet Subsequence
- 334. Increasing Triplet Subsequence
- 334. Increasing Triplet Subsequence
- 334. Increasing Triplet Subsequence
- 334. Increasing Triplet Subsequence
- 334. Increasing Triplet Subsequence
- 334. Increasing Triplet Subsequence
- 334. Increasing Triplet Subsequence
- POJ 3191The Moronic Cowmpouter
- access json.jbuilder file in api
- Android之旅第三站——活动(Activity)的携带Bundle数据的跳转…
- hosts文件的作用
- javac不是内部或外部命令
- 334. Increasing Triplet Subsequence**
- 掌握 Ajax,第 4 部分: 利用 DOM 进行 Web 响应
- 记一次企业级爬虫系统升级改造(五):基于JieBaNet+Lucene.Net实现全文搜索
- make for arm
- ReactNative热更新的实现(0.39.2)
- js或jquery如何获取父级、子级、兄弟元素
- 1042-Can't get hostname for your address , navicat无法连接mysql
- 根据不同环境读取不同配置文件
- 算法之路一USACO: YOUR RIDE IS HERE