二叉树的前序、中序、后序遍历
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分别使用traverse、divide & conquer、non-recursion来实现。
traverse使用全局遍历,不需要返回值。
divide & conquer 两步走:first :divide second:conquer
non-recursion:借助栈来实现。其中后序遍历与先右后左的前序遍历互为逆序,借助这一性质来简化操作。
traverse:
- 前序遍历
public class Solution { /** * @param root: The root of binary tree. * @return: Preorder in ArrayList which contains node values. */ public ArrayList<Integer> preorderTraversal(TreeNode root) { ArrayList<Integer> result = new ArrayList<Integer>(); traverse(root, result); return result; } private void traverse(TreeNode root, ArrayList<Integer> result) { if (root == null) { return; } result.add(root.val); traverse(root.left,result); traverse(root.right,result); }}
- 中序遍历
public class Solution { /** * @param root: The root of binary tree. * @return: Inorder in ArrayList which contains node values. */ public ArrayList<Integer> inorderTraversal(TreeNode root) { ArrayList<Integer> inorder = new ArrayList<Integer>(); traverse(root, inorder); return inorder; } private void traverse(TreeNode root, ArrayList<Integer> inorder) { if (root == null) { return; } traverse(root.left, inorder); inorder.add(root.val); traverse(root.right, inorder); }}
- 后序遍历
public class Solution { /** * @param root: The root of binary tree. * @return: Postorder in ArrayList which contains node values. */ public ArrayList<Integer> postorderTraversal(TreeNode root) { ArrayList<Integer> postorder = new ArrayList<>(); traverse(root, postorder); return postorder; } private void traverse(TreeNode root, ArrayList<Integer> postorder) { if (root == null) { return; } traverse(root.left, postorder); traverse(root.right, postorder); postorder.add(root.val); }}
Divide & Conquer
public class Solution { /** * @param root: The root of binary tree. * @return: Preorder in ArrayList which contains node values. */ public ArrayList<Integer> preorderTraversal(TreeNode root) { ArrayList<Integer> result = new ArrayList<Integer>(); if (root == null) { return result; } ArrayList<Integer> left = preorderTraversal(root.left); ArrayList<Integer> right = preorderTraversal(root.right); result.add(root.val); result.addAll(left); result.addAll(right); return result; }}
public class Solution { /** * @param root: The root of binary tree. * @return: Inorder in ArrayList which contains node values. */ public ArrayList<Integer> inorderTraversal(TreeNode root) { ArrayList<Integer> inorder = new ArrayList<Integer>(); if (root == null) { return inorder; } ArrayList<Integer> left = inorderTraversal(root.left); ArrayList<Integer> right = inorderTraversal(root.right); inorder.add(root.val); inorder.addAll(0,left); inorder.addAll(right); return inorder; }}
public class Solution { /** * @param root: The root of binary tree. * @return: Postorder in ArrayList which contains node values. */ public ArrayList<Integer> postorderTraversal(TreeNode root) { ArrayList<Integer> postorder = new ArrayList<>(); if (root == null) { return postorder; } ArrayList<Integer> left = postorderTraversal(root.left); ArrayList<Integer> right = postorderTraversal(root.right); postorder.add(root.val); postorder.addAll(0,right); postorder.addAll(0,left); return postorder; }}
Non-Recursion
public class Solution { /** * @param root: The root of binary tree. * @return: Preorder in ArrayList which contains node values. */ public ArrayList<Integer> preorderTraversal(TreeNode root) { ArrayList<Integer> preorder = new ArrayList<Integer>(); Stack<TreeNode> stack = new Stack<>(); if (root == null) { return preorder; } stack.push(root); while (!stack.isEmpty()) { TreeNode node = stack.pop(); preorder.add(node.val); if (node.right != null) { stack.push(node.right); } if (node.left != null) { stack.push(node.left); } } return preorder; }}
public class Solution { /** * @param root: The root of binary tree. * @return: Inorder in ArrayList which contains node values. */ public ArrayList<Integer> inorderTraversal(TreeNode root) { ArrayList<Integer> inorder = new ArrayList<>(); Stack<TreeNode> stack = new Stack<>(); TreeNode node = root; while (node != null || !stack.isEmpty()) { while (node != null) { stack.push(node); node = node.left; } node = stack.pop(); inorder.add(node.val); node = node.right; } return inorder; }}
public class Solution { /** * @param root: The root of binary tree. * @return: Postorder in ArrayList which contains node values. */ public ArrayList<Integer> postorderTraversal(TreeNode root) { ArrayList<Integer> postorder = new ArrayList<>(); Stack<TreeNode> stack = new Stack<>(); if (root == null) { return postorder; } stack.push(root); while (!stack.isEmpty()) { TreeNode node = stack.pop(); postorder.add(0,node.val); if (node.left != null) { stack.push(node.left); } if (node.right != null) { stack.push(node.right); } } return postorder; }}
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