HDU 1002：A + B Problem II

A + B Problem II

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 343395    Accepted Submission(s): 66615

Problem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

 

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

 

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

 

Sample Input

21 2112233445566778899 998877665544332211

 

Sample Output

Case 1:1 + 2 = 3Case 2:112233445566778899 + 998877665544332211 = 1111111111111111110

 

Author

Ignatius.L

//代码

import java.math.BigInteger;import java.util.Scanner;public class Main {public static void main(String[] args) {int t,n=1;BigInteger a,b;Scanner cin = new Scanner(System.in);t = cin.nextInt();while((t--)!=0){a = cin.nextBigInteger();b = cin.nextBigInteger();if(n!=1){System.out.println();}System.out.println("Case "+n+":");System.out.println(a+" + "+b+" = "+a.add(b));n++;}cin.close();}}

//注意

本题是一道 “大数”加法（直接用JAVA 的BigInteger简单明了）；

本体还有一个值得注意的地方，输入出格式必须是每组测试之间才有空格，有n个测试数据就要n-1个空格。