python实现简单登陆流程

来源:互联网 发布:vmtools mac 10.11 编辑:程序博客网 时间:2024/05/21 11:34
登陆流程图:


代码实现:

#-*- coding=utf-8 -*-import os,sys,getpass'''user.txt 格式账号 密码 是否锁定 错误次数jack 123 unlock 0tom 123 unlock 0lily 123 unlock 0hanmeimei 123 unlock 0lucy 123 unlock 0'''# 定义写入文件的函数def wirte_to_user_file(users,user_file_path):user_file = file(user_file_path,'w+')for k,v in users.items():line = []line.append(k)line.extend(v)user_file.write(' '.join(line)+'\n')user_file.close()# 判断用户文件是否存在,不存在直接退出user_file_path = 'users.txt'if os.path.exists(user_file_path):user_file = file(user_file_path,'r')else:print 'user file is not exists'sys.exit(1)# 遍历用户文件,将用户包装成字典users_dic = {}for user_line in user_file:user = user_line.strip().split()users_dic[user[0]] = user[1:]'''{'lucy': ['123', 'unlock', '0'], 'lily': ['123', 'unlock', '0'], 'jack': ['123', 'unlock', '0'], 'hanmeimei': ['123', 'unlock', '0'], 'tom': ['123', 'unlock', '0']}'''while True:# 输入账号input_name = raw_input('please input your username,input "quit" or "q" will be exit : ').strip()# 判断是否为退出if input_name == 'quit' or input_name == 'q':sys.exit(0)# 输入密码password = getpass.getpass('please input your password:').strip()# 判断账号是否存在、是否锁定if input_name not in users_dic:print 'username or password is not right'breakif users_dic[input_name][1] == 'lock':print 'user has been locked'break# 判断密码是否正确,正确,登陆成功if str(password) == users_dic[input_name][0]:print 'login success,welcome to study system'sys.exit(0)else:# 如果密码错误则修改密码错误次数users_dic[input_name][2] = str(int(users_dic[input_name][2])+1)# 密码错误次数大于3的时候则锁定,并修改状态if int(users_dic[input_name][2]) >= 3:print 'password input wrong has 3 times,user will be locked,please connect administrator'users_dic[input_name][1] = 'lock'wirte_to_user_file(users_dic,user_file_path)breakwirte_to_user_file(users_dic,user_file_path)


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