基于python超简洁的顺时针打印矩阵

# -*- coding:utf-8 -*-class Solution:    # matrix类型为二维列表，需要返回列表    def printMatrix(self, matrix):        # write code here        res=[]        n=len(matrix)        m=len(matrix[0])        if m==1 and n==1:            res=[matrix[0][0]]            return res        else:            for o in range((min(m,n)+1)//2):                [res.append(matrix[o][i]) for i in range(o,m-o)]                [res.append(matrix[j][m-o-1]) for j in range(o,n-o) if matrix[j][m-o-1] not in res]                [res.append(matrix[n-o-1][k]) for k in range(m-1-o,o-1,-1) if matrix[n-o-1][k] not in res]                [res.append(matrix[l][o]) for l in range(n-1-o,o-1,-1) if matrix[l][o] not in res]            return res