00003 不思议迷宫.0009.6：一键翻开石板捡取物品

         先上主要代码：

         local function onMyButton_AutoPickUpAllItems(sender, eventType)

                  if eventType ~= ccui.TouchEventType.ended then return; end

 

                  local function pickAllItems()

                          for i=1,#self.grids do

                                   local g = self.grids[i];

                                   if tiewen_canPickUpItem(g) and g.pickItemClick ~= nil then

                                            g.pickItemClick(nil, ccui.TouchEventType.began);

                                   end

                          end

                  end

 

                  local o = {};

                  o.timer = cc.Director:getInstance():getScheduler():scheduleScriptFunc(function ()

                           if self.cacheOpenGrids and #self.cacheOpenGrids > 0 then return; end

                          local g = tiewen_findGridCanBeOpenedButNotMonster(self.grids);

                          if g == nil then

                                   cc.Director:getInstance():getScheduler():unscheduleScriptEntry(o.timer);

                                   pickAllItems();

                          else

                                   if g.openGridClick ~= nil then

                                            g.openGridClick(nil, ccui.TouchEventType.began);

                                   end

                          end

               end, 0.1, false);

         end

         local apai = TieWen_UI.createButton(self, "翻板捡物", onMyButton_AutoPickUpAllItems);

         在前面我挑过原版的刺，再看看我自己的代码，只能说，我很惭愧，我的代码一样垃圾、一样的挫。哎，说似乎比做容易。

         代码中有一个地方需要说一下，就是那个红色的o。为什么要定义这么一个table而不直接使用timer呢，就如下面这样：

                  local timer = cc.Director:getInstance():getScheduler():scheduleScriptFunc(function ()

                          ……

                                   cc.Director:getInstance():getScheduler():unscheduleScriptEntry(timer);

                         ……

               end, 0.1, false);

         我看有的文章上就是这么写的。这可能和cocos2dx的版本（或者说是lua的版本）有关。在具体的这个游戏版本中，这么写是有问题的，传入scheduleScriptFunc的匿名函数被预编译，此时timer的值是nil。

function tiewen_isGridCanBeOpenedButNotMonster(grid)

         if DungeonM.canOpenGrid(grid.index) ~= GRID_OPEN_OK then return false; end

         if grid.gridData:isMonster() then return grid.gridData.monster:isDead(); end

         return true;

end

function tiewen_findGridCanBeOpenedButNotMonster(grids)

         for i=1,#grids do

            if tiewen_isGridCanBeOpenedButNotMonster(grids[i]) then return grids[i]; end

         end

         return nil

end

 

function tiewen_canPickUpItem(grid)

    if not DungeonM.checkDungeonAction() then

        -- 经检测，不允许执行地牢行为

        return false;

    end

 

         grid = grid.gridData;

    local bonus = grid.bonus;

 

    -- 不是可以拾取的类型

    if  not grid.has_key

        and grid.type ~= GRID_TYPE_BEEHIVE

        and grid.type ~= GRID_TYPE_TRAP

        and grid.type ~= GRID_TYPE_MONSTER

        and grid.type ~= GRID_TYPE_BOSS

        and grid.type ~= GRID_TYPE_ITEM

        and grid.type ~= GRID_TYPE_BOX

        and grid.type ~= GRID_TYPE_SLIME

        and grid.type ~= GRID_TYPE_APPRENTICE

        and grid.type ~= GRID_TYPE_MAP

        and grid.type ~= GRID_TYPE_BOSS_BOX

        and grid.type ~= GRID_TYPE_ACTIVITY_BOSS_BOX

        and grid.type ~= GRID_TYPE_SUMMON

        and grid.type ~= GRID_TYPE_DIAMON_STATUE

        and grid.type ~= GRID_TYPE_GOLD_CAN then

        return false;

    end

 

    -- 冈布奥和学徒

    if (grid.type == GRID_TYPE_SLIME or grid.type == GRID_TYPE_APPRENTICE) and not DungeonM.allMonsterIsDead() then

        return false;

    end

 

    -- 如果是在元素领主副本，提示击杀领主才能领取

    if UnrealDungeonM.isInAltarRuins() and not DungeonM.allMonsterIsDead() then

        return false;

    end

    -- 一些提前显示出来的奖励

    if grid:isPublicGrid() and not grid.has_key and not DungeonM.allMonsterIsDead() and grid.type ~= GRID_TYPE_TRAP and ( not grid:isMonster() or grid.monster.dbase:query("flee") == 1) then

        return false;

    end

 

    -- 如果是钥匙

    if grid.has_key then

 

        -- 如果怪物没死就不能拾取钥匙

        if grid:isMonster() then

            if not grid.monster:isDead() then

                return false;

            end

        end

    end

 

    -- 没有奖励就不能拾取

    if not bonus then

        return false;

    end

 

    -- 如果还未打开

    if not grid:isOpened() then

        return false;

    end

 

    -- 如果是怪物

    if grid:isMonster() then

        if not grid.monster:isDead() then

            return false;

        end

    end

 

    return true;

end

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