35. Search Insert Position



Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You may assume no duplicates in the array.

Here are few examples.
[1,3,5,6], 5 → 2
[1,3,5,6], 2 → 1
[1,3,5,6], 7 → 4
[1,3,5,6], 0 → 0

 public static int searchInsert_1(int[] nums, int target) {//太繁琐            int[] nums1=new int[nums.length+1];                for(int i=0;i<nums.length;i++)                {                if(nums[i]==target)                return i;                else                 {                nums1[i]=nums[i];                }                }                nums1[nums.length]=target;                                Arrays.sort(nums1);                for(int i=0;i<nums1.length;i++)                {                if(nums1[i]==target)                return i;                }                return -1;            }

 public static int searchInsert_2(int[] nums,int target)//二分查找思路            {            int low=0;            int high=nums.length-1;            while(low<=high)            {            int mid=(low+high)/2;            if(target==nums[mid])            {            return mid;            }            else if(target<nums[mid])            {            high=mid-1;            }            else            {            low=mid+1;            }            }            return low;            }