lintcode——maximum average subarray

来源:互联网 发布:c语言如何编写头文件 编辑:程序博客网 时间:2024/05/17 23:21
Given an array with positive and negative numbers, find the maximum average subarray which length should be greater or equal to given length k.
Example

Given nums = [1, 12, -5, -6, 50, 3], k = 3

Return 15.667 // (-6 + 50 + 3) / 3 = 15.667

void maxAverage(int nums[],int k,int n){ float max,c_max,t_max; for(int i=0;i<=n-k;i++) { for(int j=i;j<i+k;j++) { c_max+=nums[j]; } if(i==0) max=t_max=c_max; t_max=c_max; if(t_max>max) { max=t_max; } c_max=0; } float average=max/k; printf("maxaverage of subarray is %.5f\n",average);}void main(){ int n; printf("enter size:\n"); scanf("%d",&n); int *arr=malloc(n*sizeof(int)); printf("enter elems:\n"); for(int i=0;i<n;i++) scanf("%d",&arr[i]); int k; printf("enter k:\n"); scanf("%d",&k); maxAverage(arr,k,n);}


0 0
原创粉丝点击