2017年华为实习生招聘笔试题2

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题目如图片中所示,代码如下:


#include "stdafx.h"#include <stdio.h>#include <tchar.h>#include <iostream>int state[6] = {1,2,3,4,5,6};//存放最终状态的数组int stateL = 1;int stateR = 2;int stateF = 3;int stateB = 4;int stateU = 5;int stateD = 6;using namespace std;int main(int argc, char *argv[]){char str[50];int numCount = 0;cin.getline(str,50);for (int i = 0; i < 50; i++){if (str[i] >0x40 && str[i]<0x53){numCount++;}else{break;}}for (int j = 0; j < numCount; j++){switch (str[j]){case 'L':ActionL();break;case 'R':ActionR();break;case 'F':ActionF();break;case 'B':ActionB();break;case 'A':ActionA();break;case 'C':ActionC();break;default:break;}}cout << state[0] << state[1] << state[2] << state[3] << state[4] << state[5];    return 0;}void ActionL(void){int temp1 = 0;int temp2 = 0;temp1 = stateL;temp2 = stateR;stateL = stateU;stateR = stateD;stateD = temp1;stateU = temp2;state[0] = stateL;state[1] = stateR;state[2] = stateF;state[3] = stateB;state[4] = stateU;state[5] = stateD;}void ActionR(void){int temp1 = 0;int temp2 = 0;temp1 = stateL;temp2 = stateR;stateL = stateD;stateR = stateU;stateD = temp2;stateU = temp1;state[0] = stateL;state[1] = stateR;state[2] = stateF;state[3] = stateB;state[4] = stateU;state[5] = stateD;}void ActionF(void){int temp1 = 0;int temp2 = 0;temp1 = stateF;temp2 = stateB;stateF = stateU;stateB = stateD;stateD = temp1;stateU = temp2;state[0] = stateL;state[1] = stateR;state[2] = stateF;state[3] = stateB;state[4] = stateU;state[5] = stateD;}void ActionB(void){int temp1 = 0;int temp2 = 0;temp1 = stateF;temp2 = stateB;stateF = stateD;stateB = stateU;stateD = temp2;stateU = temp1;state[0] = stateL;state[1] = stateR;state[2] = stateF;state[3] = stateB;state[4] = stateU;state[5] = stateD;}void ActionA(void){int temp1 = 0;int temp2 = 0;temp1 = stateF;temp2 = stateB;stateF = stateL;stateB = stateR;stateL = temp2;stateR = temp1;state[0] = stateL;state[1] = stateR;state[2] = stateF;state[3] = stateB;state[4] = stateU;state[5] = stateD;}void ActionC(void){int temp1 = 0;int temp2 = 0;temp1 = stateF;temp2 = stateB;stateF = stateR;stateB = stateL;stateL = temp1;stateR = temp2;state[0] = stateL;state[1] = stateR;state[2] = stateF;state[3] = stateB;state[4] = stateU;state[5] = stateD;}



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