115:Largest Number
来源:互联网 发布:情定三生知夏向天圆房 编辑:程序博客网 时间:2024/06/05 00:12
题目:Given a list of non negative integers, arrange them such that they form the largest number.
For example, given [3, 30, 34, 5, 9] , the largest formed number is 9534330 .
Note: The result may be very large, so you need to return a string instead of an integer.
解析:这题可以先把每个整数变成字符串,得到一个字符串数组,然后把这个数组按特定规则排个序,顺序输出即可。
代码如下:
// 时间复杂度 O(nlogn),空间复杂度 O(n)class Solution {public: string largestNumber(vector<int>& nums) { vector<string> tmp; bool all_zero = true; for (auto val : nums) { if (val != 0) all_zero = false; tmp.push_back(to_string(val)); } if (all_zero) return "0"; // 考虑了输入全为 0 这种特殊情况 sort(tmp.begin(), tmp.end(), compare());// sort(tmp.begin(), tmp.end(), [=](const string& s1, const string& s2){// return (s1 + s2) < (s2 + s1); }); string result; for (int i = tmp.size() - 1; i >= 0; --i) result += tmp[i]; return result; }private: struct comapre() { bool operator()(const string& s1, const string& s2) { return (s1 + s2) < (s2 + s1); } };};
0 0
- 115:Largest Number
- Largest Number
- Largest Number
- Largest Number
- Largest Number
- Largest Number
- Largest Number
- Largest Number
- Largest Number
- Largest Number
- Largest Number
- Largest Number
- Largest Number
- Largest Number
- Largest Number
- Largest Number
- Largest Number
- Largest Number
- POJ 1511 Invitation Cards (spfa + 静态邻接表)
- alchemy
- activiti 查询流程定义启动流程
- 线段树
- 整理
- 115:Largest Number
- Python数据挖掘课程 八.关联规则挖掘及Apriori实现购物推荐
- 买不到的数目
- 测试JSR 303校验
- 神奇的复利和72法则
- window中删除服务的命令
- 线性表经常出现的算法
- 请问ANSYS Fluent 15.0如何出动画视频?
- java-final