Leetcode-58. Length of Last Word

题目

Given a string s consists of upper/lower-case alphabets and empty space characters ’ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.
找出字符串中最后一个单词的长度，如果没有则返回0

代码

class Solution {public:    int lengthOfLastWord(string s) {        int i = s.length()-1;        while(s[i] == ' ') i--;        int begin=i;        while(i >= 0 && s[i] != ' ') i--;        return begin-i;    }};