3.cout char*

 #include <iostream> using namespace std; int main(void){    char *str1 = "cout char *";    char str2[]="cout char []";    string str3="cout string";    string str5="cout string *";    string *str4=&str5;    cout<<(int *)str1<<endl<<str2<<endl<<str3<<endl<<str4;//cout char * 显示字符串而不是地址，如果要显示字符串的地址，要将 char *强制转换成其他类型例如int *再cout  }