练习3

#参数匹配，通过可变参数的匹配形式去收集#传入的参数，参数作为一个元组传入#返回交集def intersect(*args):    res=[]    for x in args[0]:        for other in args[1:]:            if x not in other:                break            else:                res.append(x)    return res#返回并集def union(*args):    res=[]    for seq in args:        for x in seq:            if not x in res:                res.append(x)    return resprint(intersect("alam","sjkm","hksk" ))print(union([1,2,3],(23,10)))