LeetCode题目：6. ZigZag Conversion Add to List

题目原址：点击打开链接 

题目描述：The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility) 
P   A   H   NA P L S I I GY   I   R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string text, int nRows);
convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".
一开始并不是很明白题目意思，查看了一下大神的解释后就明白了:
The problem statement itself is unclear for many. Especially for 2-row case. "ABCD", 2 --> "ACBD". The confusion most likely is from the character placement. I would like to extend it a little bit to make ZigZag easy understood.
The example can be written as follow:
P.......A........H.......N
..A..P....L..S....I...I....G
....Y.........I........R
Therefore, <ABCD, 2> can be arranged as:
A....C
...B....D

跟着大神的思路写了代码，思路基本和他的一样。
我的代码：
class Solution {public:    string convert(string s, int nRows) {        if(nRows==1)return s;        int l=s.size();        int r=0,t=1;        string *ss = new string[nRows];        for(int i=0;i<l;i++){            ss[r].push_back(s[i]);            if(r==0)t=1;            else if(r==nRows-1)t=-1;            r+=t;        }        string sss="";        for(int i=0;i<nRows;i++){            sss.append(ss[i]);        }        delete[] ss;        return sss;   }};

                                             
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