Spring boot发布成war包,可部署到tomcat

来源:互联网 发布:python擅长做什么知乎 编辑:程序博客网 时间:2024/05/22 00:20

1. 首先将pom.xml里面的

<packaging>jar</packaging>

改成

<packaging>war</packaging>

2. 添加依赖,如下

<!-- tomcat --><dependency>    <groupId>org.springframework.boot</groupId>    <artifactId>spring-boot-starter-tomcat</artifactId>    <scope>provided</scope></dependency>

3.build节点如下

<build>        <!-- 打包工程名 -->        <finalName>project-name</finalName>        <plugins>            <plugin>                <groupId>org.apache.maven.plugins</groupId>                <artifactId>maven-war-plugin</artifactId>                <configuration>                    <warName>wtoip-admin-common</warName>                    <failOnMissingWebXml>false</failOnMissingWebXml>                </configuration>            </plugin>            <plugin>                <groupId>org.springframework.boot</groupId>                <artifactId>spring-boot-maven-plugin</artifactId>                <version>${springboot-version}</version>            </plugin>        </plugins>    </build>

4.启动代码改造

import org.springframework.boot.SpringApplication;import org.springframework.boot.autoconfigure.SpringBootApplication;import org.springframework.boot.builder.SpringApplicationBuilder;import org.springframework.boot.web.support.SpringBootServletInitializer;import org.springframework.context.annotation.ImportResource;@SpringBootApplication(scanBasePackages={"com.test","com.test.boot"})@ImportResource("classpath:test.xml")public class TestApplication extends SpringBootServletInitializer{    public static void main(String[] args) {        SpringApplication.run(TestApplication.class, args);    }    @Override    protected SpringApplicationBuilder configure(SpringApplicationBuilder application) {        return application.sources(TestApplication.class);    }}

这样就可以开发的时候还是直接跑Java代码,打包的时候是war包了

0 0
原创粉丝点击