(LeetCode) 108. Convert Sorted Array to Binary Search Tree
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108. Convert Sorted Array to Binary Search Tree
Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
思路
将升序排序的数组变成一个平衡二叉搜索树，只需要在中间切断，将数组分为左右子树，继续递归下去。
代码
class Solution {public: TreeNode* sortedArrayToBST(vector<int>& nums) { return build(nums, 0, nums.size()-1); } TreeNode* build(vector<int>& nums, int left, int right){ if (left>right){ return NULL; } int mid = (left+right)/2; TreeNode* root = new TreeNode(nums[mid]); root->left = build(nums, left, mid-1); root->right = build(nums, mid+1, right); return root; }}; 0 0
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