c++简单24点游戏

随机生成4个代表扑克牌牌面的数字字母，程序自动列出所有可能算出24的表达式，用擅长的语言（C/C++/Java或其他均可）实现程序解决问题。

          1.程序风格良好(使用自定义注释模板)

          2.列出表达式无重复。

以下为源代码

#include<iostream>#include<string>#include <stdlib.h> #include<time.h>using namespace std;char card[] = { 'A','2','3','4','5','6','7','8','9','10','J','Q','K' };char buf[4];double nums[4];char ope[4] = { '+','-','*','/' };void cre()//生成{int i = 0;int j;cout << "生成的四张牌面为：";srand((unsigned)time(0));for (i = 0; i<4; i++){j =rand() % 13;buf[i] = card[j];}cout << buf[0] << ";" << buf[1] << ";" << buf[2] << ";" << buf[3] << "。" << endl;for (i = 0; i<4; i++){if (buf[i] == 'A') nums[i] = 1;else if(buf[i] == '2') nums[i] = 2;else if (buf[i] == '3') nums[i] = 3;else if (buf[i] == '4') nums[i] = 4;else if (buf[i] == '5') nums[i] = 5;else if (buf[i] == '6') nums[i] = 6;else if (buf[i] == '7') nums[i] = 7;else if (buf[i] == '8') nums[i] = 8;else if (buf[i] == '9') nums[i] = 9;else if (buf[i] == '10') nums[i] = 10;else if (buf[i] == 'J') nums[i] = 11;else if (buf[i] == 'Q') nums[i] = 12; else if (buf[i] == 'K') nums[i] = 13;}}double calcute(double a, double b, char index){if (index == '+') return a + b;  //若为+，则返回相应结果   else if (index == '-') return a - b;else if (index == '*') return a*b;else if (index == '/')if (b != 0)return a / b;    //只有当分母不为0时，返回结果 }void exh()//穷举计算{double  temp[3], tem[2];   //第一个符号放置后，经过计算后相当于剩下三个数，这个数组用于存储这三个数  double  sum;  //求得的和  int  judge = 0;   //判断是否找到一个合理的解   for (int i = 0; i < 4; i++)  //第一次放置的符号  {for (int j = 0; j < 4; j++)   //第二次放置的符号   {for (int k = 0; k < 4; k++)    //第三次放置的符号    {for (int m = 0; m < 3; m++)      //首先计算的两个相邻数字，共有3种情况，相当于括号的作用     {if (nums[m + 1] == 0 && ope[i] == '/') break;temp[m] = calcute(nums[m], nums[m + 1], ope[i]);temp[(m + 1) % 3] = nums[(m + 2) % 4];temp[(m + 2) % 3] = nums[(m + 3) % 4];      //先确定首先计算的两个数字，计算完成相当于剩下三个数，按顺序储存在temp数组中       for (int n = 0; n < 2; n++)       //三个数字选出先计算的两个相邻数字，两种情况，相当于第二个括号       {if (temp[n + 1] == 0 && ope[j] == '/') break;tem[n] = calcute(temp[n], temp[n + 1], ope[j]);tem[(n + 1) % 2] = temp[(n + 2) % 3];        //先确定首先计算的两个数字，计算完成相当于剩下两个数，按顺序储存在temp数组中        if (tem[1] == 0 && ope[k] == '/') break;sum = calcute(tem[0], tem[1], ope[k]);       //计算和               if (sum == 24)        //若和为24       {judge = 1;         //判断符为1，表示已求得解          if (m == 0 && n == 0)cout << "((" << nums[0] << ope[i] << nums[1] << ")" << ope[j] << nums[2] << ")" << ope[k] << nums[3] << "=" << sum << endl;else if (m == 0 && n == 1)cout << "(" << nums[0] << ope[i] << nums[1] << ")" << ope[k] << "(" << nums[2] << ope[j] << nums[3] << ")=" << sum << endl;else if (m == 1 && n == 0)cout << "(" << nums[0] << ope[j] << "(" << nums[1] << ope[i] << nums[2] << ")" << ope[k] << nums[3] << "=" << sum << endl;else if (m == 1 && n == 1)cout << nums[0] << ope[k] << "((" << nums[1] << ope[i] << nums[2] << ")" << ope[j] << nums[3] << ")=" << sum << endl;else if (m == 2 && n == 0)cout << "(" << nums[0] << ope[j] << nums[1] << ")" << ope[k] << "(" << nums[2] << ope[i] << nums[3] << ")=" << sum << endl;else if (m == 2 && n == 0)cout << nums[0] << ope[k] << "(" << nums[1] << ope[j] << "(" << nums[2] << ope[i] << nums[3] << "))=" << sum << endl;          //m=0,1,2 n=0,1表示六种括号放置可能，并按照这六种可能输出相应的格式的计算式               }}}}}}if (judge == 0)cout << "这四张扑克牌无法找到一个合理的解" << endl;  //如果没有找到结果，符号位为0 }int main(){int i;int select = 1;cout<< "################################################" << endl<< "#                                              #" << endl<< "#              欢迎进入24点游戏                #" << endl<< "#                                              #" << endl<< "################################################" << endl;while (select){cout<< "################################################" << endl<< "#                                              #" << endl<< "#                是否开始游戏                  #" << endl<< "#                                              #" << endl<< "#          0.是              1.否              #" << endl<< "#                                              #" << endl<< "################################################" << endl;cout << "请输入你的选择（0或1）：";cin >> i;switch (i){case 0:cre();exh();break;case 1:select = 0;break;default:cout << "请在0和1之间选择！" << endl;}}return 0;}