九度OJ题目1439：Least Common Multiple

题目1439：Least Common Multiple

时间限制：1 秒

内存限制：128 兆

特殊判题：否

题目描述：

The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.

输入：

Input will consist of multiple problem instances. The first line of the input will contain a single integer indicating the number of problem instances. Each instance will consist of a single line of the form m n1 n2 n3 ... nm where m is the number of integers in the set and n1 ... nm are the integers. All integers will be positive and lie within the range of a 32-bit integer.

输出：

For each problem instance, output a single line containing the corresponding LCM. All results will lie in the range of a 32-bit integer.

样例输入：

23 5 7 156 4 10296 936 1287 792 1

样例输出：

10510296

#include <stdio.h>int gcd(int a,int b){ //求最大公约数    if(b==0)    return a;    else return gcd(b,a%b);}int main(){    int n,m,a,b;    while(scanf("%d",&n)!=EOF){ //输入n，表示案例个数        for(int i=0;i<n;i++){            scanf("%d %d",&m,&a);//输入m表示该案例包含的整数个数，第一个数记为a            -- m;//m减1            while(m != 0){                 scanf("%d",&b);//输入后面的一个整数记为b                a = a/gcd(a,b)*b;//将a变成a,b的最小公倍数                --m;//m减1            }            printf("%d\n",a);//输出结果        }    }    return 0;}/**************************************************************    Problem: 1439    User: zpy    Language: C++    Result: Accepted    Time:0 ms    Memory:1020 kb****************************************************************/