leetcode#437 Path Sum III

Description:

You are given a binary tree in which each node contains an integer value.

Find the number of paths that sum to a given value.

The path does not need to start or end at the root or a leaf, but it must go downwards (traveling only from parent >nodes to child nodes).

The tree has no more than 1,000 nodes and the values are in the range -1,000,000 to 1,000,000.

对于这个题目，我们可以考虑用dp算法来考虑是否要将当前节点作为路径中的一个节点。对于取和不取当前节点，都要再对当前节点的左右儿子递归考察。但是，由于和是连续的，所以我们要用一个变量来记录是否可以跳过当前节点。总之，这道题就是一个简单的递归问题。

/** * Definition for a binary tree node. * struct TreeNode { *     int val; *     TreeNode *left; *     TreeNode *right; *     TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */class Solution {public:    int pathSum(TreeNode* root, int sum) {        return path(root, sum, true);    }    int path(TreeNode* root, int sum, bool flag) {        if (!root) return 0;        int here = 0;        if (root->val == sum) {            here = 1;        }        int left1=0, left2=0, right1=0, right2=0;        if (root->left) {            left1 = path(root->left, sum - root->val, false);            if (flag) left2 = path(root->left, sum, true);        }        if (root->right) {            right1 = path(root->right, sum - root->val, false);            if (flag) right2 = path(root->right, sum, true);        }        return here + left1 + left2 + right1 + right2;    }};