LintCode-Fizz Buzz问题

1. 描述
   给你一个整数n. 从 1 到 n 按照下面的规则打印每个数：
   如果这个数被3整除，打印fizz.
   如果这个数被5整除，打印buzz.
   如果这个数能同时被3和5整除，打印fizz buzz.
2. 样例
   比如 n = 15, 返回一个字符串数组：
   [
   “1”, “2”, “fizz”,
   “4”, “buzz”, “fizz”,
   “7”, “8”, “fizz”,
   “buzz”, “11”, “fizz”,
   “13”, “14”, “fizz buzz”
   ]
3. 代码

class Solution {public:    /**     * param n: As description.     * return: A list of strings.     */    vector<string> fizzBuzz(int n) {        vector<string> results;        for(int i=1;i<=n;i++)        {            if(i%5==0&&i%3==0)                results.push_back("fizz buzz");            else if(i%5==0)                results.push_back("buzz");            else if(i%3==0)                results.push_back("fizz");            else                results.push_back(to_string(i));        }        return results;    }};