[BZOJ4353]Play with tree(树链剖分+线段树)

来源:互联网 发布:动态分配二维数组 编辑:程序博客网 时间:2024/06/05 21:10

题目描述

传送门

题目大意:
给出一棵包含N个节点的树,设每条边一开始的边权为0,现在有两种操作:
1)给出参数U,V,C,表示把U与V之间的路径上的边权变成C(保证C≥0)
2)给出参数U,V,C,表示把U与V之间的路径上的边权加上max(C,路径上边权最小值的相反数)。
你需要统计出每次一操作过后树中边权为0的边有多少条。

题解

线段树维护区间最小值,区间最小值的个数,区间中为0的数的个数
好想好写,细节比较多。。

代码

#include<algorithm>#include<iostream>#include<cstring>#include<cstdio>#include<cmath>using namespace std;#define N 100005#define inf 1000000000int n,m,dfs_clock,Min,Sum0;int tot,point[N],nxt[N<<1],v[N<<1];int father[N],son[N],size[N],h[N],top[N],num[N];int minn[N<<2],sum0[N<<2],sum[N<<2],cover[N<<2],delta[N<<2];void add(int x,int y){++tot;nxt[tot]=point[x];point[x]=tot;v[tot]=y;}void dfs_1(int x,int fa){    size[x]=1;father[x]=fa;h[x]=h[fa]+1;    for (int i=point[x];i;i=nxt[i])        if (v[i]!=fa)        {            dfs_1(v[i],x);            size[x]+=size[v[i]];            if (size[v[i]]>size[son[x]]) son[x]=v[i];        }}void dfs_2(int x,int fa){    if (x==son[fa]) top[x]=top[fa];    else top[x]=x;    num[x]=++dfs_clock;    if (son[x]) dfs_2(son[x],x);    for (int i=point[x];i;i=nxt[i])        if (v[i]!=fa&&v[i]!=son[x])            dfs_2(v[i],x);}void update(int now){    sum0[now]=sum0[now<<1]+sum0[now<<1|1];    if (minn[now<<1]==minn[now<<1|1])    {        minn[now]=minn[now<<1];        sum[now]=sum[now<<1]+sum[now<<1|1];    }    else if (minn[now<<1]<minn[now<<1|1])    {        minn[now]=minn[now<<1];        sum[now]=sum[now<<1];    }    else    {        minn[now]=minn[now<<1|1];        sum[now]=sum[now<<1|1];    }}void pushdown(int now,int l,int r,int mid){    if (cover[now]!=inf)    {        minn[now<<1]=cover[now<<1]=cover[now];delta[now<<1]=0;        sum[now<<1]=mid-l+1;        if (!minn[now<<1]) sum0[now<<1]=mid-l+1;        else sum0[now<<1]=0;        minn[now<<1|1]=cover[now<<1|1]=cover[now];delta[now<<1|1]=0;        sum[now<<1|1]=r-mid;        if (!minn[now<<1|1]) sum0[now<<1|1]=r-mid;        else sum0[now<<1|1]=0;        cover[now]=inf;    }    if (delta[now])    {        minn[now<<1]+=delta[now];minn[now<<1|1]+=delta[now];        if (!minn[now<<1]) sum0[now<<1]=sum[now<<1];        else sum0[now<<1]=0;        if (!minn[now<<1|1]) sum0[now<<1|1]=sum[now<<1|1];        else sum0[now<<1|1]=0;        if (cover[now<<1]!=inf) cover[now<<1]+=delta[now];        else delta[now<<1]+=delta[now];        if (cover[now<<1|1]!=inf) cover[now<<1|1]+=delta[now];        else delta[now<<1|1]+=delta[now];        delta[now]=0;    }}void build(int now,int l,int r){    int mid=(l+r)>>1;cover[now]=inf;    if (l==r)    {        if (l!=1) minn[now]=0,sum0[now]=sum[now]=r-l+1;        else minn[now]=inf,sum0[now]=sum[now]=0;        return;    }    build(now<<1,l,mid);    build(now<<1|1,mid+1,r);    update(now);}void change(int now,int l,int r,int lr,int rr,int x,int opt){    if (lr>rr) return;    int mid=(l+r)>>1;    if (lr<=l&&r<=rr)    {        if (opt==1)        {            minn[now]=x;sum[now]=r-l+1;            if (!minn[now]) sum0[now]=r-l+1;            else sum0[now]=0;            cover[now]=x;delta[now]=0;        }        else        {            minn[now]+=x;            if (!minn[now]) sum0[now]=sum[now];            else sum0[now]=0;            if (cover[now]!=inf) cover[now]+=x;            else delta[now]+=x;        }        return;    }    pushdown(now,l,r,mid);    if (lr<=mid) change(now<<1,l,mid,lr,rr,x,opt);    if (mid+1<=rr) change(now<<1|1,mid+1,r,lr,rr,x,opt);    update(now);}int query(int now,int l,int r,int lr,int rr){    if (lr>rr) return inf;    int mid=(l+r)>>1,ans=inf;    if (lr<=l&&r<=rr) return minn[now];    pushdown(now,l,r,mid);    if (lr<=mid) ans=min(ans,query(now<<1,l,mid,lr,rr));    if (mid+1<=rr) ans=min(ans,query(now<<1|1,mid+1,r,lr,rr));    return ans;}void CHANGE(int x,int y,int c,int opt){    int f1=top[x],f2=top[y];    while (f1!=f2)    {        if (h[f1]<h[f2])        {            swap(f1,f2);            swap(x,y);        }        change(1,1,n,num[f1],num[x],c,opt);        x=father[f1];        f1=top[x];    }    if (num[x]>num[y]) swap(x,y);    change(1,1,n,num[x]+1,num[y],c,opt);}int QUERY(int x,int y){    int f1=top[x],f2=top[y],ans=inf;    while (f1!=f2)    {        if (h[f1]<h[f2])        {            swap(f1,f2);            swap(x,y);        }        ans=min(ans,query(1,1,n,num[f1],num[x]));        x=father[f1];        f1=top[x];    }    if (num[x]>num[y]) swap(x,y);    ans=min(ans,query(1,1,n,num[x]+1,num[y]));    return ans;}int main(){    scanf("%d%d",&n,&m);    for (int i=1;i<n;++i)    {        int x,y;scanf("%d%d",&x,&y);        add(x,y),add(y,x);    }    dfs_1(1,0);    dfs_2(1,0);    build(1,1,n);    while (m--)    {        int opt,x,y,c;scanf("%d%d%d%d",&opt,&x,&y,&c);        if (opt==1) CHANGE(x,y,c,1);        else        {            Min=QUERY(x,y);            if (Min+c<0) c=-Min;            CHANGE(x,y,c,2);        }        printf("%d\n",sum0[1]);    }}
0 0
原创粉丝点击