【LeetCode】71. Simplify Path

问题描述

https://leetcode.com/problems/simplify-path/#/description

Given an absolute path for a file (Unix-style), simplify it.

For example
path = "/home/", => "/home"
path = "/a/./b/../../c/", => "/c"

Corner Cases:

• Did you consider the case where path = “/../”?
  In this case, you should return “/”.
• Another corner case is the path might contain multiple slashes ‘/’ together, such as “/home//foo/”.
  In this case, you should ignore redundant slashes and return “/home/foo”.

算法

使用spli('/')）切割字符串，如/a/./b/../../c/切割为：['a','.','b','..','.','c','']，然后就好办了。使用一个栈来存储路径，然后遇到['.','']就跳过去，遇到'..'就将栈的最近元素弹出。

代码

public String simplifyPath(String path) {            Stack<String> stack = new Stack<>();            for(String dir:path.split("/")) {                if("..".equals(dir)) {                    if(!stack.isEmpty())                        stack.pop();                } else if(".".equals(dir)) {                    continue;                } else {                    if(!"".equals(dir)) {                        stack.push(dir);                    }                }            }            String r = "";            for(String dir:stack) {                r = r + "/" + dir;            }            return "".equals(r)?"/":r;        }